A little algebra ii - Can u solve it

[QUIET_KILLER]

[quoteost_uid0="TarkanX"]Like a few have explained, since the radius of the circle is one, the diameter of the circle is two, and if the diameter of the circle is two, then the hypotenuse of the sliced square (cut diagnolly) is two. So it would be:

a^2 + b^2 = c^2

= a^2 + b^2 = 2^2

a = b, so...

(2a^2 = 4) / (2)

= a^2 = 2

Square root both and you get:

a = square root of 2, let's see if this is correct.

v - represents square root of.

v2^2 + v2^2 = 2^2

2 + 2 = 4.

We are right, so the length and width would be v2, which is approximately 1.4142.[/quote]
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Edited By QUIET_KILLER on 1099950199