[RyusRevenge]

Ok if it was a square embedded onto the circle than its easy,

2cos45 = height
2sin45 = width

cant be bothered to look it up in the calculator, u can do that yourself .

btw if youcant work out how i come to this conclusion its simple, if a square is embedded onto the circle (i.e the corners of the square are touching the line of the circle) the diagnol across the square is the same as the diameter of the circle, therefore u are able to split the square into 2 equal triangles, the radius of the circle is 1, therefore the diameter is 2.

diameter 2 = hypotenuse

a square has 90 degrees at each vertex, since we split it into 2 equal triangles, it has become an acute angle of 45 degrees.

So now we have 2 vital peices of info, the hypotenuse which is 2 and the acute angle of the triangle which is 45 degrees, simple pythagoras can be used to work out the other two sides - width and height.



Edited By RyusRevenge on 1099727907