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I had this on a test and my teach told us it was simple but nobody gets it right see if youcan solve it
A rectangle(could possibly be a square by definition) is inscribed in a circle with a radius of 1. What are the length and width of that rectangle. if youget an answer post it and ill be able to tell the answer on Monday Edited By KenDaShoto on 1099703503 |
That sound more like a bit of Geometry.
First, the square is cut into two peices, making 2 triangles, and if the radius is 1, then the diameter is 2, making the base of each triangle 2. So, the sides are half which would make it 1, making the width and height 1...but I can't remember the name of the unit. |
you need to be alot more specific
what units are you using? does the rectangle have to have all corners touching the circle? |
i take algebra 2 and i know thats geomarty easy question i dont hink i should give u the answer.
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Yeah, more info. It's been years since I've done this stuff, no wonder my brain hurts so much, I don't have enough info =\
Jay_dizzle: Yeah, you sound really convincing :sarcasm: |
yeah it does need more info but really ive done this stuff before come on now y would i lie about this.
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thats all the info we got the rectangle is inscribed so yes all corners touch the circle and it cant be h=1 and L=1 because it is a right triangle and L squared + W squared has to equal 4
units dont matter because ur answer would have the same # if it were in in. or cm. come on if the prob. was that simple i wouldnt have made this post, and Jay Dizzle i already took the test so post ur answer and ill tell U if youwere right when my teach tells us the answer and it is Algebra 2 were doing conic sections Edited By KenDaShoto on 1099714214 |
surely there's a diagram representing this..could you possibly draw it
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Units have to be different if your converting a radius to L and H. And you said it was a rectangle, a square, in the circle, now your saying it's a triangle?
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[quote:post_uid0="KenDaShoto"]I had this on a test and my teach told us it was simple but nobody gets it right see if youcan solve it
A rectangle(could possibly be a square by definition) is inscribed in a circle with a radius of 1. What are the length and width of that rectangle. if youget an answer post it and ill be able to tell the answer on Monday[/quote] your missing one bit of info, currently it is impossible to answer, think back.....(u can have different sized rectangles enclosed into the circle, therefore you would need another peice of info, maybe the width of it or maybe the area of the occupying rectangle than it will be possible to answer). Edited By RyusRevenge on 1099726377 |
let me see...
The square is cut diagonally with the length of the diameter of the circle, 2. By Pythagoras thm, base sq+ height sq = Diagonal sq x sq + x sq = 2sq 2x sq = 4 x sq = 2 x = sq root 2 = 1.14 |
Ok if it was a square embedded onto the circle than its easy,
2cos45 = height 2sin45 = width cant be bothered to look it up in the calculator, u can do that yourself ;). btw if youcant work out how i come to this conclusion its simple, if a square is embedded onto the circle (i.e the corners of the square are touching the line of the circle) the diagnol across the square is the same as the diameter of the circle, therefore u are able to split the square into 2 equal triangles, the radius of the circle is 1, therefore the diameter is 2. diameter 2 = hypotenuse a square has 90 degrees at each vertex, since we split it into 2 equal triangles, it has become an acute angle of 45 degrees. So now we have 2 vital peices of info, the hypotenuse which is 2 and the acute angle of the triangle which is 45 degrees, simple pythagoras can be used to work out the other two sides - width and height. Edited By RyusRevenge on 1099727907 |
Like a few have explained, since the radius of the circle is one, the diameter of the circle is two, and if the diameter of the circle is two, then the hypotenuse of the sliced square (cut diagnolly) is two. So it would be:
a^2 + b^2 = c^2 = a^2 + b^2 = 2^2 a = b, so... (2a^2 = 4) / (2) = a^2 = 2 Square root both and you get: a = square root of 2, let's see if this is correct. v - represents square root of. v2^2 + v2^2 = 2^2 2 + 2 = 4. We are right, so the length and width would be v2, which is approximately 1.4142. Edited By TarkanX on 1099766839 |
yea thats what i put on the test but im not sure if thats right
and units dont matter and thats all the info we got so stop askin for more Edited By KenDaShoto on 1099770511 |
runs far away*
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[quote:post_uid0="TarkanX"]Like a few have explained, since the radius of the circle is one, the diameter of the circle is two, and if the diameter of the circle is two, then the hypotenuse of the sliced square (cut diagnolly) is two. So it would be:
a^2 + b^2 = c^2 = a^2 + b^2 = 2^2 a = b, so... (2a^2 = 4) / (2) = a^2 = 2 Square root both and you get: a = square root of 2, let's see if this is correct. v - represents square root of. v2^2 + v2^2 = 2^2 2 + 2 = 4. We are right, so the length and width would be v2, which is approximately 1.4142.[/quote] The bits in italic is what i understood up too. |
well i expected to post the answer today but my teacher didnt come to school today so maybe tomorrow
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[quote:post_uid0="TarkanX"]Like a few have explained, since the radius of the circle is one, the diameter of the circle is two, and if the diameter of the circle is two, then the hypotenuse of the sliced square (cut diagnolly) is two. So it would be:
a^2 + b^2 = c^2 = a^2 + b^2 = 2^2 a = b, so... (2a^2 = 4) / (2) = a^2 = 2 Square root both and you get: a = square root of 2, let's see if this is correct. v - represents square root of. v2^2 + v2^2 = 2^2 2 + 2 = 4. We are right, so the length and width would be v2, which is approximately 1.4142.[/quote] I didn't know that Algebra 2 had those sectionz :biggrin: Soundz like it has reached the cubic centrum of pyronali Hirez tarkanjetix to do his homework for $4.00 for the rest of his life :biggrin: muahaha Warmor is next savez another $4.00 :cheesy: Ah yes I remember I bought that hickamadothingi What does a zingyryu do again can some one tell me oh yeah. Nice it sayz conker for $1.00 can't beat that For that price on www.sfo-ebay.com You can even biy a nferni336 comic book a collectible They have Warmorticuspheus pasta sauce Great wit french fryz and frenchtoast Now they have the new seriez of lefty wrench set It comez with a variety of fb rachetz and A torque rachet can't be that eh people skaweet :kungfu: I am only J/K :biggrin: Tarkan x twas a nice explanation go supa madiyo guardian Edited By QUIET_KILLER on 1099950199 |
good thing quiet killer cause before i saw that u were just kidding u made me want to close the topic before i gave the answer
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still hasnt given back the test and wont til friday so.... yeah
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I wonder if people even read quiet killer's posts...with all the poetry
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ok the square root is correct but i missed the part in the problem when it said the area of the rectangle as well as the radius is 1 so if anyone can figure out the answer to the problem if the area of the rectangle is 1 then post it if youare in algebra II or have had it you will have a good chance of figuring this out cause it is really simple
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sorry i tryed, but im not a nerd..
i say 1.5372 |
don't you listen to your math teacher a square can be called a rectangle. So the the radius is 1 so 1+1=2 so the diameter is to so i'm guessing the length and width is 1 unit or 1 cm or 1 inch or what ever the units are.
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no thats not right not tryin to be mean or anything but i suggest u put what u said in the pythagorean theroem and you will see that that cant be true and if anyone is going to actually attempt to solve this i will tell u that using systems of equations will be your best bet and if no one really cares let me know and ill just close the topic
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